3.16. Mixed-Up Code Exercises¶

Answer the following Mixed-Up Code questions to assess what you have learned in this chapter.

Construct a function that correctly prints the integer conversion of the passed double.

```
cout << d;
```
```
cout d;
```
```
d = int(d);
```
```
d = integer(d);
```
```
print_integer (double d);
```
```
void print_integer (double d) {
```
```
}
```

Construct a function called new_line that takes no arguments and prints a blank line. Then construct another function called divider that prints two blank lines separated by a line of ". . . . . . . . . . . ."

cout << ". . . . . . . . . . . . " << '\n';

```
cout << '\n';
```
```
cout << new_line ();  //first call
```
```
cout << new_line ();  //second call
```
```
new_line ();  //first call
```
```
new_line ();  //second call
```
```
void divider () {
```
```
void divider (new_line) {
```
```
void new_line () {
```
```
}  //divider
```
```
}  //new_line
```

Construct a function that correctly calculates the volume of a cone with as much precision as possible and prints the value to the terminal.

```
constexpr double pi = 3.1415926;
```
```
cout << vol;
```
```
double vol = 1/3 * pi * r * r * h;
```
```
double vol = 1/3.0 * pi * r * r * h;
```

double volume_cone (double r, double h) {

```
int vol = 1/3 * pi * r * r * h;
```
```
int vol = 1/3.0 * pi * r * r * h;
```
```
void volume_cone (double r, double h) {
```
```
}
```

Construct a function that prints the sin of an angle given in degrees.

```
#include &#60;cmath&#62;
```

#include &#60;iostream&#62;
using namespace std;

```
#include &#60;math&#62; #distractor
```
```
constexpr double pi = 3.1415926;
```
```
cout <<  sin(d);
```
```
cout <<  sin(r);
```
```
double r = d * (2 * pi) / 360.0;
```
```
double r = d * 360.0 / (2 * pi);
```
```
void sine_degrees () {
```
```
void sine_degrees (double d) {
```
```
}
```

Construct a function that prints the price (with 8% sales tax) of an item with after using a 30% off coupon.

```
cout << final;
```
```
double discount = item * 0.30;
```

double final = (item - discount) * 0.08;

double final = (item - discount) * 1.08;

```
double final = item - discount * 0.08;
```
```
void final_price (double item) {
```
```
void final_price (string item) {
```
```
}
```

Suppose you have already defined a function called sum_of_squares which returns the sum of the squares of two numbers and sqrt which returns the square root of a number. Construct a function that calculates the hypotenuse of the right triangle and prints the three sidelengths.

cout << "The sides of the triangle are: " << s1 << ", " << s2 << ", " << hypot;

cout << "The sides of the triangle are: " << s1 << ", " << s2 << ", " << s3;

```
double hypot = sqrt(s1, s2);
```
```
double hypot = sqrt(sum);
```
```
double s1 = 4.8;
double s2 = 3.8;
```
```
double sum = sum_of_squares(s2, s1);
```
```
int main () {
```
```
int s1 = 4.8;
int s2 = 3.6;
```
```
sum = sum_of_squares(s1, s2);
```
```
}
```

The chickens from the previous chapter are infuriated. Construct a function that prints "Eat" on the first line, "More" on the second line, and the name of the passed animal on the fourth line, followed by an exclamation point.

```
cout << "Eat" << '\n';
```
```
cout << "Eat";
```
```
cout << '\n';
```
```
cout << '\n'; cout << "More" << '\n';
```
```
cout << animal << ! << '\n';
```
```
cout << animal << '!' << '\n';
```
```
void eat_more () {
```
```
void eat_more (string animal) {
```
```
}
```

Construct a function that takes a dollar amount and cent amount and prints the total amount of money that you have. Hint: the mod operator (%) returns the remainder of a division.

cout << '$' << dollar_total << '.' << cent_total;

cout << '$' << dollar_total << cent_total;

```
double cent_total = cents % 100;
```
```
double cent_total = cents / 100;
```

double dollar_total = dollars + cents / 100.0;

int dollar_total = dollars + cents / 100;

```
void print (int dollars, int cents) {
```
```
}
```

In Michigan, the probability that it snows on any given day in the winter is about 14%. The probability of having a snow day on any given day in the winter is about 4%. The probability that is snows and you have a snow day is 8%. Construct and call a function that calculates the probability of having a snow day, given the fact that it will snow tonight. For reference, the formula for conditional probability is: P(A|B) = P(B and A) / P(B).

conditional_probability(p_snow, p_both);

conditional_probability(p_snowday, p_both);

conditional_probability(p_snowday, p_snow);

```
cout << prob;
```

double p_snow = 0.14;
double p_snowday = 0.04;
double p_both = 0.08;

```
double prob = B / both;
```
```
double prob = both / B;
```
```
int main () {
```

void conditional_probability (double B, both) {

void conditional_probability (double B, double both) {

```
} //conditional_probability
```
```
} //main
```

Q10

Your final grade is determined by a midterm component (each midterm is worth 20% of the grade) and a final component. In order to avoid any discrepancies with students who's grades are on the fence, your teacher follows this strict grading scale: [0%,60%) = F, [60%, 70%) = D, [70%, 80%) = C, [80%, 90%) = B and [90%, 100%] = A. They do not truncate until the very end. Construct a function that determines your final grade percentage according to this grading scheme and prints the result.

```
cout << grade;
```
```
cout << int(grade) + 1;
```
```
cout << int(grade);
```
```
double grade = m_comp + f_comp;
```

double m_comp = m1 * 0.2 + m2 * 0.2;
double f_comp = f * 0.06;

int m_comp = m1 * 0.2 + m2 * 0.2;
int f_comp = f * 0.06;

void final_grade (double m1, double m2, double f) {

```
void final_grade (double m1, m2, f) {
```
```
}
```