3.16. Mixed-Up Code Exercises

Answer the following Mixed-Up Code questions to assess what you have learned in this chapter.

Construct a function that correctly prints the integer conversion of the passed double.

        void print_integer (double d) {
---
print_integer (double d); #paired
---
 d = int(d);
---
 d = integer(d); #paired
---
 cout << d;
---
 cout d; #paired
---
}
        

Construct a function called newLine that takes no arguments and prints a blank line. Then construct another function called divider that prints two blank lines separated by a line of “… … … …”

        void new_line () {
---
 cout << endl;
---
}  //new_line
---
void divider () {
---
 void divider (newLine) { #paired
---
 new_line ();  //first call
---
 cout << new_line ();  //first call #paired
---
 cout << ". . . . . . . . . . . . " << endl;
---
 new_line ();  //second call
---
 cout << new_line ();  //second call #paired
---
}  //divider
        

Construct a function that correctly calculates the volume of a cone with as much precision as possible and prints the value to the terminal.

        void volume_cone (double r, double h) {
---
double volume_cone (double r, double h) { #paired
---
 constexpr double pi = 3.1415926;
---
 double vol = 1/3.0 * pi * r * r * h;
---
 double vol = 1/3 * pi * r * r * h; #paired
---
 int vol = 1/3 * pi * r * r * h; #paired
---
 int vol = 1/3.0 * pi * r * r * h; #paired
---
 cout << vol;
---
}
        

Construct a function that prints the sin of an angle given in degrees.

        #include <cmath>
---
#include <iostream>
using namespace std;
---
void sine_degrees (double d) {
---
void sine_degrees () { #paired
---
 constexpr double pi = 3.1415926;
---
 double r = d * (2 * pi) / 360.0;
---
 double r = d * 360.0 / (2 * pi); #paired
---
 cout <<  sin(r);
---
 cout <<  sin(d); #paired
---
}
---
 #include <math> #distractor
        

Construct a function that prints the price (with 8% sales tax) of an item with after using a 30% off coupon.

        void final_price (double item) {
---
void final_price (string item) { #paired
---
 double discount = item * 0.30;
---
 double final = (item - discount) * 1.08;
---
 double final = (item - discount) * 0.08; #paired
---
 double final = item - discount * 0.08; #paired
---
 cout << final;
---
}
        

Suppose you have already defined a function called sum_of_squares which returns the sum of the squares of two numbers and sqrt which returns the square root of a number. Construct a function that calculates the hypotenuse of the right triangle and prints the three sidelengths.

        int main () {
---
 double s1 = 4.8;
 double s2 = 3.8;
---
 int s1 = 4.8; #paired
 int s2 = 3.6;
---
 double sum = sum_of_squares(s2, s1);
---
 sum = sum_of_squares(s1, s2); #paired
---
 double hypot = sqrt(sum);
---
 double hypot = sqrt(s1, s2); #paired
---
 cout << "The sides of the triangle are: " << s1 << ", " << s2 << ", " << hypot;
---
 cout << "The sides of the triangle are: " << s1 << ", " << s2 << ", " << s3; #paired
---
}
        

The chickens from the previous chapter are infuriated. Construct a function that prints “Eat” on the first line, “More” on the second line, and the name of the passed animal on the fourth line, followed by an exclamation point.

        void eat_more (string animal) {
---
void eat_more () { #paired
---
 cout << "Eat";
---
 cout << "Eat" << endl; #paired
---
 cout << endl; cout << "More" << endl;
---
 cout << endl;
---
 cout << animal << "!" << endl;
---
 cout << animal << ! << endl; #paired
---
}
        

Construct a function that takes a dollar amount and cent amount and prints the total amount of money that you have. Hint: the mod operator (%) returns the remainder of a division.

        void print (int dollars, int cents) {
---
 int dollar_total = dollars + cents / 100;
---
 double dollar_total = dollars + cents / 100.0; #paired
---
 double cent_total = cents % 100;
---
 double cent_total = cents / 100; #paired
---
 cout << '$' << dollarTotal << '.' << centTotal;
---
 cout << '$' << dollarTotal << centTotal; #paired
---
}
        

In Michigan, the probability that it snows on any given day in the winter is about 14%. The probability of having a snow day on any given day in the winter is about 4%. The probability that is snows and you have a snow day is 8%. Construct and call a function that calculates the probability of having a snow day, given the fact that it will snow tonight. For reference, the formula for conditional probability is: P(A|B) = P(B and A) / P(B).

        void conditional_probability (double B, double both) {
---
void conditional_probability (double B, both) { #paired
---
 double prob = both / B;
---
 double prob = B / both; #paired
---
 cout << prob;
---
} //conditional_probability
---
int main () {
---
 double pSnow = 0.14;
 double pSnowday = 0.04;
 double pBoth = 0.08;
---
 conditional_probability(pSnow, pBoth);
---
 conditional_probability(pSnowday, pBoth); #paired
---
 conditional_probability(pSnowday, pSnow); #paired
---
} //main
        

Your final grade is determined by a midterm component (each midterm is worth 20% of the grade) and a final component. In order to avoid any discrepancies with students who’s grades are on the fence, your teacher follows this strict grading scale: [0%,60%) = F, [60%, 70%) = D, [70%, 80%) = C, [80%, 90%) = B and [90%, 100%] = A. They do not truncate until the very end. Construct a function that determines your final grade percentage according to this grading scheme and prints the result.

        void final_grade (double m1, double m2, double f) {
---
void final_grade (double m1, m2, f) { #paired
---
 double m_comp = m1 * 0.2 + m2 * 0.2;
 double f_comp = f * 0.06;
---
 int m_comp = m1 * 0.2 + m2 * 0.2; #paired
 int f_comp = f * 0.06;
---
 double grade = m_comp + f_comp;
---
 cout << int(grade);
---
 cout << int(grade) + 1; #paired
---
 cout << grade; #paired
---
}
        

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