6.8. Mixed-Up Code Exercises

Answer the following Mixed-Up Code questions to assess what you have learned in this chapter.

Construct a function that prints whether a number is true.

        void is_true (int number) {
---
bool is_true (int number) { #paired
---
 if (number % 2 == 0) {
---
  cout << true;
 }
---
 else {
---
  cout << false;
 }
---
}
        

Construct a function that prints the difference of a and b if the result would result in a positive number. Otherwise, prints -1.

        void difference (int a, int b) {
---
int difference (int a, int b) { #paired
---
 if (a - b > 0) {
---
 if (a - b < 0) { #paired
---
  cout << a - b;
 }
---
 else {
---
  cout << -1;
 }
---
}
        

Construct a block of code that prints “automatic” if x is an odd number, “systematic” if x is greater than y, AND “hydromatic” if y is not equal to x. Check all 3 conditions.

        if (x % 2 == 1) {
---
if (x % 2 == 0) { #paired
---
 cout << "automatic"; }
---
if (x > y) {
---
else if (x > y) { #paired
---
 cout << "systematic"; }
---
if (y != x) {
---
else { #paired
---
 cout << "hydromatic"; }
        

Construct a block of code that prints “Pick me!” if x is equal to y, “Choose me!” if x is less than y, OR “Love me!” if x + y is even.

        if (x == y) {
---
if (x = y) { #paired
---
 cout << "Pick me!"; }
---
else if (y > x) {
---
if (x < y) { #paired
---
 cout << "Choose me!"; }
---
else if ((x + y) % 2 == 0) {
---
else (x + y % 2 == 0) { #paired
---
else if (x + y % 2 == 0) { #paired
---
 cout << "Love me!"; }
        

Construct a function that prints your letter grade according to this scheme. [0, 70) = F, [70, 80) = C, [80, 90) = B, and [90, 100] = A.

        void printLetterGrade (double grade) {
---
 if (grade < 70) {
---
  cout << "F"; }
---
 else if (grade < 80) {
---
 if (grade < 80) { #paired
---
  cout << "C"; }
---
 else if (grade < 90) {
---
 if (grade < 90) { #paired
---
  cout << "B"; }
---
 else {
---
 else if (grade < 100) { #paired
---
 if (grade < 100) { #paired
---
  cout << "A"; }
---
}
        

According to a logic game, a knight is someone who cannot tell a lie, and a knave is someone who cannot tell the truth. Construct a function that takes two booleans: the truth value of the story, and the truth value told by the person. The function should print whether the person was a knight or a knave.

        void knightKnave (bool truth, bool told) {
---
 if (truth == true) {
---
  if (told == true) {
   cout << "Knight";
  }
---
  else {
   cout << "Knave";
  } }
---
 else {
---
  if (told == true) {
   cout << "Knave";
  }
---
  else {
   cout << "Knive";
  } }
---
}
        

If a cat is in a good mood, it purrs; when it’s in a bad mood, it meows. If a doog is in a good mood, it barks; when it’s in a bad mood it woofs. Construct a function that accomplishes this.

        void makeVocals (string animal, string mood) {
---
 if (mood == "bad") {
---
  if (animal == "dog") {
   cout << "Woof!";
  }
---
  else {
   cout << "Meow!";
  }
---
 else {
---
  if (animal == "dog") {
   cout << "Bark!";
  }
---
  else {
   cout << "Purr!";
  }
---
}
        

Construct a recursive function that tells the user to enter a positive number. It should then output that number to the terminal. If the user enters a negative number or zero, prompt the user again.

        void takeSum () {
---
 cout << "Input a positive number!";
---
 int num;
 cin >> num;
---
 if (num < 0) {
---
  takesum ();
---
 } // END "if"
---
 cout << num;
---
} // END function
        

In the table of ASCII characters, the lowercase alphabet consists of characters 97-122. The uppercase alphabet consists of characters 65-90, which is a 32 character shift back from the lowercase. Construct a recursive function that asks the user to input a LOWERCASE character, converts that character to UPPERCASE character and prints it. If the user enters a character outside of the range of the LOWERCASE alphabet, prompt the user again. Hint: “||” means “or” when used between two conditional statements.

        void capitalize () {
---
 cout << "Input a lowercase character!";
---
 char let;
 cin >> let;
---
 if (int(let) < 97 || int(let) > 122) {
---
  capitalize (); }
---
 let = let - 32;
---
 cout << char(let);
---
}
        

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